首先，题意需要明确，让我门尝试nothing的值，我们猜测这是一个变量
http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=abc
页面返回了：and the next nothing is 6711
接着我们尝试：http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=6711
页面返回了：and the next nothing is 2795
….
这就是一个循环
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import urllib, re, time uri = "http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=%s" nothing_rep = "and the next nothing is (\d+)" nothing = "18022" # You'll later be asked to change this # to "46059" and re-run the script. while True: try: print "start" source = urllib.urlopen(uri % nothing).read() print source nothing = re.search(nothing_rep, source).group(1) except: break print nothing |
第一次执行之后返回的结果是：
…
16044
start
Yes. Divide by two and keep going.
这个时候，我们要修改一下我们的程序，把参数设置为16044/2
然后继续
然后得到结果：
peak.html